Flanagan's physics according to Flanagan's equations!

©2025 GOLDTREE Publishing  Dear viewers, I hope you are ready to be wowed by our latest quantum news update! Using ‘F = ma’ we know that the force on a mass 'm' at a point where the gravitational intensity of a planet is 'g' is 'mg'.  But this force is also given by ‘F = GMm/r²’ where ‘M’ is the mass of the planet and ‘r’ is the distance from its centre.  The equation represents the attractive force (F) of two masses (M) and (m) separated at distance (r).   Interestingly, F = GmM/r² = ma = mv²/r = qvO, where F is for force, G is for the gravitational constant, M is the mass of the planet and r is the distance from its centre, the equation represents the attractive force F of two masses M and m separated at distance r. m is for mass, a is for acceleration, v is for velocity q is for the gravitational charge and O is for the gravitational field.   Furthermore: qvO = ma = mv²/r = G(Mm/r²) = eV Where ( m ) is for mass and ( v ) is for velocity ( M ) is the...